目录列表更多的方法列表的嵌套总结
列表更多的方法index():返回指定数据所在位置的下标 (注意:如果查找的数据不存在则报错。)。count():统计指定数据在当前列表中出现的次数。len():访问列表⻓度,即列表中数据的个数。in:判断指定数据在某个列表序列,如果在返回True,否则返回Falsenot in:判断指定数据不在某个列表序列,如果不在返回True,否则返回Falseappend():列表结尾追加数据。extend():列表结尾追加数据,如果数据是⼀个序列,则将这个序列的数据逐⼀添加到列表。insert():指定位置新增数据。pop():删除指定下标的数据(默认为最后⼀个),并返回该数据。remove():移除列表中某个数据的第⼀个匹配项。clear():清空列表逆置:reverse()排序:sort()copy()`def generateRandomList(a, b, n, random_state): from random import randint, seed seed(random_state) ls = [] for i in range(n): ls.append(randint(a, b)) return lsls = generateRandomList(0, 100, 10, 666)print(ls) # [58, 48, 55, 36, 64, 1, 70, 70, 99, 91]
print(ls.index(55)) # 2print(ls.index(70)) # 6print(ls.index(70, 7, 9)) # 7
print(ls.count(70)) # 2print(ls.count(58)) # 1print(ls.count(666)) # 0
print(len(ls))
for i in range(len(ls)): print(ls[i])for x in ls: print(x)
def my_index(ls, val): for i in range(len(ls)): if ls[i] == val: return i return -1print(“myindex = “, my_index(ls, 70))print(“myindex = “, my_index(ls, 101))
print(69 in ls)print(70 in ls)print(70 not in ls)print(69 not in ls)
hero_ls = []hero_ls.append(“鲁班七号”)hero_ls.append(“妲己”)hero_ls.append(123)print(hero_ls)hero_ls.insert(1, “校领导”)hero_ls.insert(1, “校领导夫人”)print(hero_ls)hero_ls.extend(“BBQ”)print(hero_ls)hero_ls.extend([‘瑶’, ‘暃’])hero_ls.extend([‘123’])print(hero_ls)
print(hero_ls.pop())print(hero_ls.pop())print(hero_ls.pop(1))print(hero_ls)hero_ls.remove(‘妲己’)print(hero_ls)hero_ls.clear()print(hero_ls)
lss = [1, 2, 3, 4, 5]lss.reverse()print(lss)
print(ls)ls.sort()print(ls)ls.sort(reverse=True)print(ls)
nls = lss.copy()print(nls)print(nls)列表的嵌套
列表中还有列表, 可以表示数学中的矩阵
name_list = [[‘⼩明’, ‘⼩红’, ‘⼩绿’], [‘Tom’, ‘Lily’, ‘Rose’], [‘张三’, ‘李四’, ‘王五’]]print(name_list[1])print(name_list[1][0])练习
# 设计一个函数, 生成 n 行的 直角三角形 *, 存储到列表中返回def generate(n): total_ls = [] for i in range(n): ls = [] for j in range(i+1): ls.append(‘ ‘) total_ls.append(ls) return total_lsprint(generate(6))for row in generate(6): for v in row: print(v, end=’’) print()
def send1(money, count): money*=100 #分 m = money//count # 每一份的金额 l = money%count bag = [] for i in range(count-1): bag.append(m/100) if l == 0: bag.append(m/100) else: bag.append((m+l)/100) return bagprint(send1(100, 3))
def send2(money, count): money = 100 # 分 from random import randint bag = [] for i in range(count - 1): m = money // count cur = 2randint(0, m-1) money -= cur bag.append(cur/100) bag.append(money/100) return bagprint(send2(100, 3))print(sum(send2(100, 3)))
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